[cig-commits] r15079 - in short/3D/PyLith/trunk/tests/1d: line2 line3

brad at geodynamics.org brad at geodynamics.org
Thu May 28 14:29:05 PDT 2009


Author: brad
Date: 2009-05-28 14:29:04 -0700 (Thu, 28 May 2009)
New Revision: 15079

Modified:
   short/3D/PyLith/trunk/tests/1d/line2/README
   short/3D/PyLith/trunk/tests/1d/line3/README
Log:
Added line3 full-scale tests.

Modified: short/3D/PyLith/trunk/tests/1d/line2/README
===================================================================
--- short/3D/PyLith/trunk/tests/1d/line2/README	2009-05-28 21:22:24 UTC (rev 15078)
+++ short/3D/PyLith/trunk/tests/1d/line2/README	2009-05-28 21:29:04 UTC (rev 15079)
@@ -1,4 +1,4 @@
-Full-scale tests for 1-D bar.
+Full-scale tests for 1-D bar with linear cells.
 
 0      1      2      3      4
 * ---- * ---- * ---- * ---- *
@@ -13,7 +13,7 @@
 
 AXIAL EXTENSION
 
-1-D axial extension test with linear cells.
+1-D axial extension.
 
 Dirichlet boundary conditions
   u(0) = -0.2
@@ -25,7 +25,7 @@
 
 DISLOCATION
 
-1-D axial extension with dislocation test with linear cells.
+1-D axial extension with dislocation.
 
 Dirichlet boundary conditions (same as extension)
   u(0) = -0.2

Modified: short/3D/PyLith/trunk/tests/1d/line3/README
===================================================================
--- short/3D/PyLith/trunk/tests/1d/line3/README	2009-05-28 21:22:24 UTC (rev 15078)
+++ short/3D/PyLith/trunk/tests/1d/line3/README	2009-05-28 21:29:04 UTC (rev 15079)
@@ -1,6 +1,5 @@
-1-D axial extension test with quadratic cells.
+Full-scale tests for 1-D bar with quadratic basis functions.
 
-
 0      1      2      3      4
 * -----*----- * -----*----- *
 
@@ -11,9 +10,31 @@
   3        3.0
   4        4.0
 
+
+AXIAL EXTENSION
+
+1-D axial extension
+
 Dirichlet boundary conditions
   u(0) = -0.2
   u(4) = +0.2
 
 Analytical solution
   u(x) = -0.2 + 0.1 * x
+
+
+DISLOCATION
+
+1-D axial extension with dislocation
+
+Dirichlet boundary conditions (same as extension)
+  u(0) = -0.2
+  u(4) = +0.2
+
+Dislocation (1-D fault).
+  u(2+)-u(2-) = D(2) = 0.5
+
+Analytical solution
+  u(x<2) = -0.20 - 0.025 * x
+  u(x>2) = +0.30 - 0.025 * x
+



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